|Introduction to Cell & Molecular Biology (BIOL121) - Dr. S.G. Saupe (firstname.lastname@example.org); Biology Department, College of St. Benedict/St. John's University, Collegeville, MN 56321|
Mechanisms of Heredity
Have you ever wondered why offspring look like their parents? The answer - genetics. During the next two classes we will study how this process works.
Sex determination - a review
Let's start with sex!
Sex chromosomes are those that carry important
information for determining sex. There
are two sex chromosomes in mammals,
X and Y. The X chromosome, which is
much larger than the Y, has a centrally-positioned centromere. All
other chromosomes are termed autosomes. Humans
have 46 total chromosomes: 44 autosomes and
2 sex chromosomes. Or, 22 pairs
(homologous chromosomes) of autosomes and 1 pair of sex chromosomes.
The sex chromosomes are homologous to one another.
Normal females have two XX chromosomes, normal males have an X and Y chromosome. Nettie Sloan first discovered this is 1900. Thus, after meiosis, all female eggs will have one X chromosome, whereas, 50% of sperms will carry the X chromosome and 50% the Y chromosome (see diagram in class). When sperm and egg recombine, there is a 50% chance of having a female, and 50% chance of having a male. We can set up a Punnet square to represent this situation.
Thus, there is 1:1 ratio of male to female
offspring or 1 in 2 (1/2) chance of having a boy or girl or 50% chance of having
a girl or boy. In practice slightly
more males are conceived, possibly because the Y carrying
sperm swim faster.
state that the
male determines the sex of the child. This
is true only in the sense
that sperms come in two "flavors" (X and Y), whereas eggs in only one
(X). Thus, depending
upon which sperm fertilizes the egg, that will determine the sex of the
Non-disjunction at meiosis (or mitosis) is one cause of unusual combinations of chromosomes (a cell/individual with odd numbers of chromosomes is termed aneuploid). Nondisjunction is the failure of chromosomes to properly segregate during meiosis. In other words, it is a violation of the Law of Segregation. Nondisjunction can occur at meiosis I or II. (see diagrams).
aneuploids include: XXX - triple X
syndrome, female, 47; XXY - Kleinfelters
syndrome, male, 47, (frequency about 1 in 1000 live births); XYY - male, 47; XO
- Turner's syndrome, female, 45 (about 1 in 5000 live births); Down's syndrome (trisomy
21; frequency increases with maternal age).
Cells can tolerate imbalances of sex chromosomes better than imbalances of autosomes. With the exception of Down's syndrome and a couple of others like Edwards syndrome (trisomy 18) or Patau's (trisomy 13), there are few live births of autosomal aneuploids and individuals are severely afflicted. Why are cells able to tolerate extra sex chromsomes? Because....
X chromosomes are inactivated so they don't "mess things
Lyon first observed that in normal females only one X
chromosome remains active, any additional ones are inactivated during
development (after about 10 embryonic divisions).
The inactivated X chromosome forms a small dark staining spot in
a Barr body. This forms the
basis for the sex test. Thus,
only one remains active,
the others inactivate as Barr bodies. Barr
body number: XX - 1 Barr body; XXX
- 2 barr bodies; XXY - 1 Barr body; XYY - no Barr body; XY - no Barr body.
(Note: the chromosome that is
inactivated is at random.); and
chromosomes are small
and carry comparatively little genetic information that will "mess
A karyotype is used to determine the chromosome composition of an individual. White blood cells are typically used (red cells lack a nucleus), they are treated with colchicine which prevents the formation of microtubules. Thus, cell division stops at metaphase, allowing a good view of the spread chromosomes. The chromosomes are stained, photographed and arranged from large to small, matching homologs (see exercise).
Some parents want to know if the offspring they are carrying is "normal." Amniocentesis (removal of amniotic fluid containing fetal cells is obtained) or chorionic villi biopsy (remove some of fringe around embryo) permit sampling of fetal tissue to determine karyotype and other genetic conditions.
color in cats: X-linked trait
Let's talk about cats, specifically calico cats which are orange, black and white. The coat color gene is carried on the X chromosome. Thus this gene is called X-linked (or sex-linked for a more general term). There are two forms of expression (called alleles) for this trait - XO and XB. The XO allele codes for orange pigmentation and the XB for black spots. If both alleles of a pair are the same, we call it homozygous; if they are different, heterozygous. Thus, in a diploid cell there are three possible combinations of alleles: XO XO, XO XB, and XB XB. Cats with these combinations appear: white with orange spots, white with black and orange spots (calico), and white with black spots, respectively. The actual genetic composition is called the genotype, and the expression of the genes is the phenotype. Thus, calico is the phenotype for a cat with the genotype XO XB.
Note that so far we have only considered female cats.
Male cats can have the genotype
XB Y or XOY.
The phenotype of the first would be white with black spots,
the second will have orange spots. Thus,
all calico cats are female! (there
is the rare
sterile male with the genotype XO
As an aside, recall that the X chromosome that becomes inactive as a Barr body does so randomly. This explains why calico cats have random splotches of black or orange, depending upon which chromosome carrying which allele was inactivated in the cell line that gave rise to that part of the cat. Also note that these alleles are codominant; that is, both are expressed in the heterozygote. In many cases, one allele (dominant) dominates over the expression of the other (recessive). Thus, heterozygotes will express the dominant trait.
Question: What offspring, and in what proportion, would you expect between a calico female and black spotted male?
Answer: 1/4 (or 25%) calico female, 1/4 black spot female, 1/4 black spot male, 1/4 orange spot male
X-linked traits in humans
These include hemophilia, colorblindness (recessive), muscular dystrophy (recessive), Lesch-Nyhan (recessive), and hypophosphatemia (dominant).
Let's use hemophilia, a disorder where the blood fails to properly clot, as a model. There are two alleles for this trait H - normal and h - hemophilia. Thus, there are five possible genotypes (and phenotypes): XH XH(normal female), XH Xh (normal female, carrier of hemophilia), Xh Xh (female hemophiliac), XH Y(normal male), Xh Y (hemophiliac male). Note that in the heterozygous condition, that normal condition dominates over the expression of hemophilia. Thus the normal allele is dominant to the hemophilia allele which is recessive. For recessive traits to appear in the phenotype, they need to be present in the homozygous condition. Dominant traits are expressed in the homozygous or heterozygous state.
Because females must receive two recessive alleles to express the trait, X-linked traits are usually rarer in females than males.
Question: What offspring and what frequency do you expect from a marriage between a hemophiliac male and a normal female whose father had hemophilia? We call the parents the parental generation, symbolized by P, and their offspring the first filial generation (F1). The offspring from the F1 generation are called the F2 generation (second filial generation)?
Answer: We know the male genotype must be XhY since he shows the hemophilia phenotype. A normal female can have the genotype XHXH or XHXh. However, we know this female must be XHXh (a carrier) since her father had hemophilia - she inherited his X chromosome. Thus, we can set up a Punnett Square:
Thus, in the first filial generation, 50% of the offspring would be hemophiliacs and 50% normal. 50% of both females and males would be normal and 50% hemophiliac.
Y-linked traits in humans
There aren't too many. These traits would obviously be passed from father to son. Hairy ears and testosterone production (SRY gene) are two genes located on the Y chromosome.
Autosomal Traits in Humans
So far we have only discussed genes that are carried on the sex chromosomes. Obviously, the autosomes carry genes, too. In fact, the majority of the genes are carried on the autosomes.
There are a variety of traits in humans that seem to inherit as though they are controlled by a single gene (for a listing click here). As you study this list and complete the handout, remember that each trait is specified by a single gene that is found on one of the 22 pairs of homologous autosomes. Each homolog is carrying one allele for the gene. The two alleles may be the same (homozygous) or different (heterozygous). One allele may dominate (dominant) over the expression of the other (recessive).
Geneticists use one or three letter abbreviations to represent a gene. Thus we used the letter "H" to represent the gene for blood clotting above. In the case where one allele is dominant over another, the dominant allele is expressed with capital letters and the recessive allele with lower case (for blood clotting example: H = normal clotting; h = hemophilia)..
Let's give another example. If we are interested in the tongue-rolling gene, we could symbolize it with the letter "R". We would use a capital "R" to represent the dominant allele and a lowercase "r" to represent the recessive allele. If neither allele is dominant, different letters can be used (as in the calico cat example) or perhaps the prime (') symbol. For example, we could express the two alleles as R and R'.
Since these alleles are not found on the sex chromosome and their expression is unrelated to the sex of the individual, we don't need to include the designation X or Y when writing the genotypes of the autosomes. Thus, tongue rolling is symbolized RR or Rr or rr not XRXr or XrXr or XRY or XrY.
Another symbol commonly used is "+" to represent the "wild type" or normal condition. Then, the "mutant" condition would be represented with a letter symbol.
Some take-home-lessons from the Single Gene Handout:
Dominant traits are not necessarily the most common ones;
You may not have enough information to determine your genotype for many traits - those that you show the dominant phenotype.
are two ways to determine your genotype of an individual that show the
(a) Pedigree analysis - study the parents. If one parent shows the recessive trait, then the offspring must be heterozygous; and
(b) Perform a Test Cross - mate an individual with the dominant phenotype to an individual that is homozygous recessive. If the recessive phenotype occurs in the offspring, then the individual must have been heterozygous. Obviously this is not possible with humans, but is commonly used for other organisms.
|Test Cross Example
Consider a pea plant with purple flowers (dominant phenotype). Is this individual homozygous (PP) or heterozygous (Pp)? To answer this question, we perform a test cross. The plant in question is mated with a true-breeding plant that produces white (pp) flowers. If our unknown is homozygous (PP), then 100% of the offspring would be expected to be purple-flowered:
However, if the unknown is heterozygous (Pp), then 50% of the offspring would be predicted to be white flowered, and 50% purple flowered (see the Punnett square below). There would be a 1 : 1 ratio of white-to-purple flowered plants.
Solving Genetics Problems
Now you are almost ready to solve some genetics problems involving a single gene - called monohybrid crosses. Here are a few additional tips:
the information that you know, i.e., how many genes are involved, how
many alleles are involved, what are the alleles, do the alleles show
dominance/recessive or codominance? do you know the genotypes of parents or
is the ratio of the offspring. If the offspring exhibit a 3:1 ratio
then the parent's must be heterozygous.
A 1:1 ratio indicates that one parent is homozygous recessive
and the other is heterozygous. A 1:2:1 ratio of phenotypes indicates
that the alleles exhibit incomplete dominance as in snapdragon flower color.
A 9:3:3:1 ratio of offspring indicates a mating between two parents
heterozygous for two genes. A 1:1:1:1 ratio indicates a mating between two
parents, one heterozygous and the other homozygous recessive for two traits.
Rule of Multiplication - to determine the probability of two unrelated events occurring, multiply the probability of the individual events. Consider a couple who want two children.
What is the probability that child #1 is a girl? Answer = 50% or 0.5
What is the probability that child #2 is a girl? Answer = 50% or 0.5
What is the probability that both children will be girls? Answer = since there are independent events, the probability is the product of their individual probabilities: 0.5 x 0.5 = 0.25 = 25% or 1/4
Check out the problems at the end of the chapter or provided on-line. The more problems you work, the better you will understand it. We'll work some together in class.
Lessons From a Monk: Gregor Mendel
Called the "Father" of genetics. Normally, I would use gender-inclusive language and call such a person the "Founder" of Genetics. In this case, "Father" is correct because Mendel was monk in the monastery of St Thomas, Brunn (now Brno) near Vienna. He was born in 1822. He published the first work on genetics in 1865 called "On the Nature of Inheritance". He studied the inheritance of traits in peas.
Peas were a terrific choice because:
there were lots of hybrids that had previously been studied;
there were true breeding varieties available (i.e., when allowed to self pollinate or mated with another individual of the same type, they produced more of the same variety);
they are small, easy to grow and have a reasonably short life cycle;
the flowers are good for breeding studies (readily self pollinate, easy to remove stamens for cross pollination studies).
Mendel's work was ignored for 35 years, when it was simultaneously "discovered" by three botanists (Tschermak, Correns, de Vries). It was ignored because it was:
too sophisticated using brilliant, carefully controlled experiments (he was a man ahead of his times);
too much math/stats for people to understand;
published in an obscure journal;
Mendel was not in the scientific mainstream; and
he stated his ideas poorly (a good reason to do well in Symposium!).
Mendel studied 7 different traits (genes) each with two forms of expression (alleles) These are
These genes are located on 4 of the 7 pairs of homologous chromosomes (2n=14).
Flower color and seed color are on chromosome 1; flower position, pod
shape, and plant height are on chromosome 4; pod color on chromosome 5; and seed
shape on chromosome 7.
So, what were Mendel's actual contributions? He determined:
Hereditary information is transmitted in particles or units (that we now call genes). [A gene specifies a particular trait or feature of an individual. The phenotype is the outward expression of the genes and the genotype refers to the specific genetic makeup that translates into the phenotype];
There are two factors (allele) for every trait in a diploid individual (on homologous chromosomes) [An allele is the form of expression of a gene];
The two alleles may be the same (homozygous) or different (heterozygous);
Alleles don't blend their expression, like mixing a can of paint. This seems obvious now, but the dominant paradigm of the day was that alleles blended. For example cross a red flower with a white flower to get pink which becomes would become diluted more and more in subsequent crosses. In contrast, if alleles are discrete, then mix red and white and get pink, but mix pink and pink and you could get back red and white;
One unit from every pair moves into gametes during meiosis (Law of Segregation). In other words, homologous chromosomes separate during meiosis;
The expression of one allele (dominant) usually predominates over the other (recessive);
act independently of one another (i.e., Law of Independent Assortment,
homologous chromosomes separate randomly in meiosis).
This is the situation where there are more than two alleles at a locus responsible for a particular trait. (versus two alleles for all the traits that we have discussed so far). A good example is the ABO blood groups in humans.
Three alleles are responsible for ABO blood type. These are:
IA - this allele codes for A antigens on the cell surface of the red blood cells (an antigen is a substance that stimulates the production of an antibody. Specifically, this gene causes galactosamines to be attached to lipids on the cell surface);
IB - specifies B antigens on rbc (adds galactose to cell surface lipids); and
i (or O) - no antigens on cell surface.
Thus, an individual can have the following phenotypes/genotypes:
|Blood type||Genotype (s)||Antigen on RBC surface||Antibodies in plasma|
|A||IAIA , IA i||A||antibodies against B (anti B)|
|B||IBIB, IB i||B||antibodies against A (anti A)|
|AB||IAIB||A and B||none (= universal recipient)|
|O||ii||none (= universal donor)||anti A and anti B|
These alleles are codominant (one does NOT dominant over the expression of
the other). In other words, in the
heterozygote, both are expressed in the phenotype.
As an aside, if
you have type A blood, you have antibodies against type B antigens.
Antibodies react with the antigens that stimulated its production to
remove it from
the body. Individuals with type B
blood have antibodies against type A antigens, type
O blood has antigens against both A and B antigens and individuals with AB blood
have no antibodies. Thus, type O
blood is the universal donor (since it has no antigens
on rbc, it won't be attacked by either antibody) and type AB is the universal
recipient (because it has no antibodies, won't react with either A or B
of blood types: Crosses work just
like others described above. For example:
a mother with type AB blood and a father with type AB.
What progeny and
in what proportions do you expect? Answer:
1/4 type A, 1/4 type B, 1/2 type AB.
two parents, one type A and the other type B.
Can they have a child with
type A blood? type B?
type AB? type O?
Answers: It depends on
the actual genotypes
of the parents.
Consider a family in which the father has type B blood, the child type A blood and the mother type O blood. Dad says he's not the father of the child. What do you conclude? Answer: Dad is right. Since we know the mother of the child has type O blood the child must have at least one "i" allele. Thus, the other allele is "A". Since the father is type B, he could not have contributed the A allele, and therefore, is not the father. Note: blood genetics can confirm a person is NOT a parent, but cannot prove that a person IS the parent
These are another type of antigen found on red blood cells. They were first recognized in rhesus monkeys, hence the abbreviation. Either your rbc cells have the antigens (RH+) or not (Rh-). Rh positive individuals never produce antibodies against Rh antigens. Rh negative individuals don't normally produce antigens but can be induced to do so if exposed to Rh+ blood (as might happen in a transfusion, which is unlikely in modern medicine, or it could easily happen if an Rh- mom gives birth to an Rh+ child). In the latter case, the mother is given a shot of rhogam soon after delivery to scavenge up the Rh+ antigens to prevent her immune system from producing Rh antibodies that might affect subsequent children.
This is another example of a trait coded by multiple alleles and by two genes. One gene with two alleles (R+, R-) codes for the production of red pigment and a second gene with multiple alleles codes for the amount of pigment deposited in the hair (bd - blonde, light deposition; Bw - brown, medium deposition; Bk - black, heavy deposition). As a result, a large number of hair colors, from strawberry blonde to glossy black, possible.
Incomplete Dominance & Summary/Review of relationships between alleles
Incomplete dominance is the situation in which neither allele dominates over the expression of the other. Rather, the heterozygote shows an intermediate expression of the phenotype. The classic example is flower color in snap dragons. Two alleles are responsible for flower color, R - red and R' - allele. Thus, there are three genotypes/phenotypes: RR - red flowers, RR' - pink flowers, and R'R' - white flowers.
A cross between two pink flowering plants will yield an expected phenotypic
ratio of 1:2:1, or in other words, 1/4 are expected to be red, 1/4 white and 1/2
pink. The 1:2:1 ratio
should be a good clue that you are dealing with incomplete dominance.
of allelic relationships: If
in the heterozygote.... one
allele is expressed, then it's said to be dominant both
alleles are expressed, then it's said to be codominant neither
allele is expressed but appears blended, then it is said to be incomplete
Summary of allelic relationships:
If in the heterozygote....
one allele is expressed, then it's said to be dominant
both alleles are expressed, then it's said to be codominant
neither allele is expressed but appears blended, then it is said to be incomplete dominance
Linked genes are those that are found on the same pair of homologous chromosome. Earlier we discussed sex linkage which refers to genes found on the X (or Y) chromosome. Thus, their inheritance is linked with sex. Obviously, countless autosomal genes are linked. If you assume that humans have about 50,000 genes (Human Genome Project) and since there are 23 pairs of homologous chromosomes, on average, there must be about 2000 genes per chromosome (50,000/23). Those that are found on the same pair of homologous chromosomes are linked.
Let's return to Mendel's work with peas to provide some examples: The seed texture gene and the seed color genes are not linked because they occur on different chromosomes - seed texture is on chromosome #7 and seed color on chromosome #1. The genes for flower color and seed color are linked - they are both carried on chromosome #1. How about the genes for pod shape and stem height; are they linked?
Individuals that differ in two traits. In class, we will go through a worksheet together examining a cross in peas. Points to note: (a) dihybrid crosses involved two genes, each usually with two alleles; (b) if the genes are not linked, then a completely heterozygous individual can produce four types of gametes; (c) a mating between two completely heterozygous individuals results in 4 types of offspring, in a ratio of 9:3:3:1. In other words, 9/16 show the two dominant traits, 1/16 show the two recessive traits, 3/16 are recessive for one trait and dominant for the other, and the other 3/16 show the same thing only reversed; (d) a mating between a heterozygous individual and homozygous recessive results in a ratio of 1:1:1:1 ratio; and (e) linkage results in unexpected ratios of offspring.
A fun example from a bird lover: Color
in parakeets (budgies, which is short for budgerigars).
Two genes that are not linked are responsible for feather color.
One gene codes for the production
of a melanin in the center of the shaft (B = blue/black; b = no blue black 'cuz
no melanin in center of shaft). The
other gene codes for a yellow pigment in the other
part of the feather (Y = yellow pigment, y = no yellow).
Thus four phenotypes are
possible: Green birds (B_Y_); blue (B_yy); Yellow (bbY_); and white (bbyy).
Consider a cross between a heterozygous green bird and a white one.
and in what frequency do you expect? Answer:
1/4 green; 1/4 blue; 1/4
yellow; 1/4 white.
The exchange of portions of chromatids during meiosis will result in new combinations of alleles in chromosomes. See worksheet in class. Take home lesson: recombinant gametes/offspring are those that are the product of a crossing over and usually occur in low frequency. The frequency of crossing over is related to the distance the genes are separated on the chromosome. That is, the further apart the two loci are, the greater the probability that crossing over will occur between the two.
Situation where a single gene affects many traits. In other words, a one gene has many different effects. (note this is in contrast to situations were have discussed above where one gene affects one trait).
A good example is Marfan's Syndrome, also called Abe Lincoln disease.
This is caused
by a dominant allele and it results in the production of abnormal connective
tissue. Afflicted individuals have
skeletal problems (long limbs, loose joints), cardiovascular
problems and eye defects. Lincoln
was described as tall and lanky. There
is some evidence he was not well during the last years of his life and may have
been afflicted with this disease. Some
think he may have died from it had he not been
This is where a single trait is influenced by many genes. It is common, especially in traits that exhibit continuous variation (no clear cut differences) such as height, eye color or skin color.
For example, there are at least three genes involved in eye color.
One gene codes
for melanin production (yes = normal, dominant allele, no = albino, recessive).
A second gene determines whether melanin is deposited in the outer layer of the
iris of the eye (yes = some shade of brown, dominant; no = blue).
The third gene(s) determines
the density or amount of melanin deposited in the iris.
Thus, eye color is the
result of production, distribution and concentration of melanin in the eye.
If no melanin,
then the eye appears red, from the blood vessels at the back of the eye.
is produced, it is placed in the retina. The
eye will appear blue as light
off the retina. Melanin deposited
in the iris will result in a shade of brown.
reflects off the retina. Melanin deposited in the iris will result in a shade of brown.
This is the situation where one gene influences the expression of another. In other words, genes interact with one another. Eye color is one good example. If there is no melanin producing gene, then the other genes cannot be expressed.
Sweet pea flower
color. Note this trait is coded for by
two genes that aren't linked. Assume
that you cross purple (PPCC) and white (ppcc) flowering plants.
The F1 will all
be PpCc or purple flowering. A
cross between two heterzygotes will result in an F2 ratio
of 9:7 (purple to white). The
purple trait will only be expressed if both genes have
dominant alleles. The reason is
because the pigment is made by a multistep pathway,
similar to the production of adenine yeast.
� (P gene)
� anthocyanin (purple pigment). Thus,
both P and C must be present to make the
The environment influences the expression of genes. Note that the expression of any gene is modified by its environment. Some classic examples: Siamese cats (yuck) have black appendages cuz its cooler, genes produce melanin. The leaves of aquatic plants vary depending upon whether they are submerged or floating.
Last updated: July 14, 2009 � Copyright by SG Saupe